2x^2+11x-25=0

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Solution for 2x^2+11x-25=0 equation: 



2x^2+11x-25=0

a = 2; b = 11; c = -25;
Δ = b2-4ac
Δ = 112-4·2·(-25)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{321}}{2*2}=\frac{-11-\sqrt{321}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{321}}{2*2}=\frac{-11+\sqrt{321}}{4}
$

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